Math, asked by Kesaramji, 11 hours ago

8y-5/7y+1=5/4 solve and verify the answer​

Answers

Answered by ZaraAntisera
3

Answer:

\frac{8y-5}{7y+1}=\frac{5}{4}\quad :\quad y=-\frac{25}{3}\quad \left(\mathrm{Decimal}:\quad y=-8.33333\dots \right)

Step-by-step explanation:

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

\left(8y-5\right)\cdot \:4=\left(7y+1\right)\cdot \:5\left(8y-5\right)\cdot \:4=\left(7y+1\right)\cdot \:5

32y-20=35y+5

\mathrm{Add\:}20\mathrm{\:to\:both\:sides}

32y-20+20=35y+5+20

32y=35y+25

\mathrm{Subtract\:}35y\mathrm{\:from\:both\:sides}

32y-35y=35y+25-35y

-3y=25

\mathrm{Divide\:both\:sides\:by\:}-3

\frac{-3y}{-3}=\frac{25}{-3}

y=-\frac{25}{3}

Answered by patnaiksrinivasrao59
1

Answer:

Attached it.

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