Question

8y² – 9y + 1 = 0 solution for this problem

Answer 1

Answer:

$y = \frac{ - 1}{8} \: or \: y = - 1$

Step-by-step explanation:

$8 {y}^{2} - 9y + 1 = 0$

$8 {y}^{2} - (8 + 1)y + 1 = 0$

$8 {y}^{2} - 8y - 1y + 1 = 0$

$8y(y + 1) + 1(y + 1) = 0$

$(y + 1)(8y + 1) = 0$

$y + 1 = 0 \: or \: 8y + 1 = 0$

$y = - 1 \: or \: y = \frac{ - 1}{8}$

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Answer 2

Answer:

y = 1. or. y = 1/8

Step-by-step explanation:

8y^2 - 9y +1 =0

8y^2 - 8y - y +1 =0

8y(y - 1) - 1(y - 1) =0

(y - 1) (8y - 1) =0

therefore,

y = 1. or. y = 1/8