8yz – 10z +12y – 15 can be factorized as
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Answer:
(4y-5)(2z+3)
Step-by-step explanation:
rearrange: 8yz+12y-10z-15
(8yz+12y)(-10z-15)
in (8yz+12y) the common factor is 4y
and in (-10z-15) the common factor is -5
therefore 4y(2z+3)-5(2z+3)
(2z+3) is common so it becomes one factor and the other factor is (4y-5)
and that is how you get your answer as (4y-5)(2z+3)
hope this helps you out
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