Question

9.0 gram glucose ko 100 gram water me ghola gaya hai viliyan ki molarta gyat kijiye.(c=12 h=1 o=16)​

Answer 1

Answer:

sorry I don't know your answer

Answer 2

a-solute

b- solvent

Moles=n

$n a = \frac{w}{mol.wt} = \frac{180}{9} = 20$

$nb = \frac{100}{18} = 5.55$

$total \: moles = 20 + 5.55$

$total \: moles = 25.5$

$moles \: soln = \frac{v \: soln}{22.4} \\ v \: soln = 25.5 \times 22.4 \\ vsoln = 571.2$

$molarity = \frac{na}{vol \: soln } \\ molarity = \frac{20}{571.2} \\ molarity = 0.035$

I hope this helps( ╹▽╹ )