(9^1/3 * 27^-1/2) / (3^1/6 * 3^-2/3)
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Answer:
Solution
(9^1/3 * 27^-1/2)/(3^1/6 * 3^-2/3)
(3^2/3 * 3^-3/2)/(3^1/6*3^-2/3)
Use property with same base
a^x * a^y = a^(x+y)
(3^{2/3 -3/2}) /(3^{1/6 -2/3)
Now Take LCM of
(3^{[4-9]/6}) /(3^{[3-12]/18})
(3^{-5/6}) /(3^{-9/18})
(3^{-5/6}) /(3^{-1/2})
Use property
x^a/x^b = x^(a-b)
(3^{-5/6 - 1/2})
(3^{[-10-6]/12})
(3^{-16/12})
(3^{-4/3})
or
1/(3^{4/3})
Hopefully you got it.
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