Question

9 1 by 3 upon 3 1 by 6 into 27 1 by 2 upon 3 1 by 3​

Answer 1

Answer:

3^5/3

Step-by-step explanation:

Given  

9 1 by 3 upon 3 1 by 6 into 27 1 by 2 upon 3 1 by 3

Given  

 9^1/3 x 27^1/2 / 3^1/6 x 3^1/3

We can write it as

(3^2)1/3 x (3^3)^1/2 / 3^1/6 x 3^1/3

We know that a^m x a^n = a^m + n and a^m / a^n = a^m – n

3^2/3 + 3/2 – 1/6 – 1/3

3^4 + 9 -1 – 2 / 6

3^10/6

3^5/3