Question

9,10,11

with full explanation.
I will mark as brainliest. ​

Answer 1

Answer:

Hi mate ur 10th questions ans

Step-by-step explanation:

Let the sum be P. Rate = 10% C.I. for third year = Amount at the end of 3rd year – Amount at the end of 2nd year = p [1+ 10/ 100]3 - p [ 1+10/100]2 =p { (11/10)3 - (11/10)2} = p (11/10)2 (11/10- 1) =p x 121/100 x 1/10 = 121/1000 P C.I.for first year = Px10x1 / 100 = p / 100 ( S. I. = PxRxT/100) According to the question 121/1000 P - P/100=252 (121-100 / 1000) P = 252 21/100 P = 252 Ans is, P= 12000/-