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ASSESSMENT
Find the least number which when divided by 12, 15, 20 and 24 leaves the same remainder 2 in each case ?
Answers
Answered by
0
Step-by-step explanation:
24 = 2^2 * 3 ; So the LCM is 2^3 * 3 * 5 = 120 . So the number that we want is 127 .
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Answered by
0
Answer:
ans=lcm
120
Step-by-step explanation:
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