Question

9. 100 mL of a solution of sodium hydroxide is found to be completely
neutralised by 80 mL of given solution of hydrochloric acid to form aqueous
solution of sodium chloride (Salt).
What will be the amount of hydrochloric acid required to neutralise
200 mL of the same solution of sodium hydroxide?
OR​

Answer 1

Answer:

Since NaOH is a monoprotic basic then 0.5 N NaOH = 0.5 M NaOH or 0.5 mole/L = 0.5 x 40 g NaOH/L or 20 g in 1 L of solution. Thus, the amount of NaOH present in 200 mL is 200/1000 mL x 20 g = 4 g.

Answer 2

Answer:

160 ml of HCl is required to neutralize 200ml of naoh