Question

9/13×(a+b)=a(5/7)+b(8/13)​

Answer 1

★ ⦋Answer⦌

$\large{\frac{9}{13} ×(a+b)=a( \frac{5}{7} )+b( \frac{8}{13} )} \\ \implies \frac{9a + 9b}{13} = \frac{5a}{7} + \frac{8b}{13} \\ \implies\frac{9a + 9b}{13} - \frac{5a}{7} - \frac{8b}{13} = 0 \\ \implies \frac{63a + 63b - 65a - 56b}{91} = 0 \\ \implies \frac{7b - 2a}{91} = 0 \\ \implies7b - 2a = 0 \\ \because \: 7b = 2a \: \: \: \: \: \: \: \: \: \: or. - 2a = - 7b \\ \\ \because \: b = \frac{2a}{7} \: \: \: \: \: \: \: \: \: \: \: \: or. \: \: a = \frac{7b}{2}$

Answer 2

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$\frac{9}{13} \times (a + b) = a( \frac{5}{7} ) +b (\frac{8}{13} )$

$➪ \frac{9a + 9b}{13} = \frac{5a}{7} + \frac{8b}{13}$

$➪ \frac{9a + 9b}{13} - \frac{5a}{7} - \frac{8b}{13 = 0}$

$➪ \frac{63a + 63b - 65a - 56b}{91} = 0$

$➪ \frac{7b - 2a}{91} = 0$

$➪ 7b - 2a = 0$

$➪7b = 2a$

$➪b = \frac{2 a}{7}$