9
13) find the value of Sin²A+cos²A sec²A-tan²A
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Answer:
1-cos^2A+cos^2A×(1+tan^2A)-tan^2A
1-cos^2A+cos^2A+tan^2Acos^2A-tan^2A
1+tan^2(cos^2-1)
sec^2×-1(1-cos^2)
sec^2×-1(sec^2)
sec^2×-1/sec^2
= -1
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