Math, asked by Sushwak, 7 months ago

9 = 16
1) Ravi's father bought two houses: one for 3 12,56,000 and the other for
23,48,000. How much did he spend altogether? By how much was the
second house more expensive than the first?​

Answers

Answered by asha202
5

Step-by-step explanation:

Ravi’s father bought first house for Rs12,56,000 and he bought second house for Rs23,48,000.

The total money used will be,

Rs12,56,000+Rs23,48,000=Rs36,04,000

The difference between the both costs is,

Rs23,48,000−Rs12,56,000=Rs10,92,000

Therefore, the second house is Rs10,92,000 expensive than the first house....

prefer it child

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