Question

(9/16×4/12) + (9/16× -3/9)​

Answer 1

Solution :-

→ $(\frac{9}{16} \times \frac{4}{12}) + (\frac{9}{16} \times \frac{-3}{9})$

→ $(\cancel \frac{9}{16} \times \cancel \frac{4}{12}) + (\cancel \frac{9}{16} \times \cancel \frac{-3}{9})$

→ $(\frac{3}{4} \times \frac{1}{4}) + (\frac{1}{16} \times \frac{-3}{1})$

→ $\frac{3}{16} + \frac{-3}{16}$

→ $\frac{3 + (-3)}{16}$

→ $\frac{3 - 3}{16}$

→ $\frac{0}{16}$

→ 0 ÷ 16 = 0

→ 0 (Ans)

Therefore, we have got the answer of :-

$(\frac{9}{16} \times \frac{4}{12}) + (\frac{9}{16} \times \frac{-3}{9})$ which is 0.

Hope it will help you.