Question

9^-2×18^-4/3^-16 solve ​

Answer 1

Answer:

${9}^{ - 2} \times {18}^{ - 4} \div {3}^{ - 16} \\ \frac{ {9}^{ - 2} \times {18}^{ - 4} }{ {3}^{ - 16} } \\ = \frac{ {3}^{16} }{ {9}^{2} \times {18}^{4} } \\ = \frac{ {3}^{16} }{ ({3}^{2})^{2} \times {(9 \times2)}^{4} } \\ = \frac{ {3}^{16} }{ {3}^{4}\times ({3}^{2})^{4} \times{2}^{4} }\\ =\frac{ {3}^{16} }{ {3}^{4}\times {3}^{8} \times{2}^{4} } \\ =\frac{ {3}^{16} }{ {3}^{4+8}\times {2}^{4} }\\= \frac{ {3}^{16} }{ {3}^{12}\times {2}^{4} }\\ = \frac{ {3}^{16 - 12} }{ {2}^{4} } \\ = \frac{ {3}^{4} }{ {2}^{4} } \\ = ( { \frac{3}{2} )}^{4} \\ = \frac{81}{16} \\ = \: \: \underline{ \underline{ 5 \frac{1}{16} }}$