Math, asked by Anonymous, 5 months ago

9^-2×18^-4/3^-16 solve ​

Answers

Answered by harshitha926594
0

Answer:

 {9}^{ - 2}  \times  {18}^{ - 4}   \div  {3}^{ - 16}  \\  \frac{ {9}^{ - 2} \times  {18}^{ - 4}  }{ {3}^{ - 16} } \\  =  \frac{ {3}^{16} }{ {9}^{2} \times  {18}^{4}  }   \\  =  \frac{ {3}^{16} }{ ({3}^{2})^{2} \times  {(9 \times2)}^{4}  }  \\  =  \frac{ {3}^{16} }{ {3}^{4}\times ({3}^{2})^{4} \times{2}^{4}  }\\ =\frac{ {3}^{16} }{ {3}^{4}\times {3}^{8} \times{2}^{4}  } \\ =\frac{ {3}^{16} }{ {3}^{4+8}\times {2}^{4}  }\\=  \frac{ {3}^{16} }{ {3}^{12}\times {2}^{4}  }\\ =   \frac{ {3}^{16 - 12} }{ {2}^{4} }  \\  =  \frac{ {3}^{4} }{ {2}^{4} }  \\ =  ( { \frac{3}{2} )}^{4}  \\  =  \frac{81}{16}  \\  = \:  \:  \underline{ \underline{ 5 \frac{1}{16} }}

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