Question

[9-{(2÷2-1)×4-7}+6] solve this same of 6th class

Answer 1

To Solve :

• [9-{(2÷2-1)×4-7}+6]

About the Concept :

• In this question we will be using BODMAS. Now what is BODMAS ? BODMAS states that firstly we have to solve for brackets, then we have to solve for off , then we have to solve for division , after that we have to solve for multiplication , after that we have to solve for addition and at last we have to solve for subtraction. Full form of BODMAS is :
• B = Brackets
• O = Off
• D = Division
• M = Multiplication
• A = Addition
• S = Subtraction

Solution :

• [ 9 - {(2 ÷ 2 - 1) × 4 - 7} + 6 ]
• [ 9 - {(1 - 1) × 4 - 7} + 6 ]
• [ 9 - {1 × 4 - 7} + 6 ]
• [ 9 - {4 - 7} + 6 ]
• [ 9 - {-3 } + 6 ]
• [ 9 + 3 + 6 ]
• [ 9 + 9 ]
• 18

Therefore :

• Required answer is 18

Important Rules :

• - (-) = +
• - (+) = -
• + (+) = +
• + (-) = -
• This rules states that that when minus will be multiplied by minus then the result will be in plus.
• This rules states that that when minus will be multiplied by plus then the result will be in minus.
• This rules states that that when plus will be multiplied by plus then the result will be in plus.
• This rules states that that when plus will be multiplied by minus then the result will be in minus.

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