Question

9 + 2 = 711
14 + 6 = 820
17 + 11 = 628
12 + 3 = ?????

a) 15 b)115 c)915 d)12​

Answer 1

Answer:

915

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Answer 2

Answer:

2 + 9 = 711

14 + 6 = 820

17 + 11 = 628

12 + 3 = ?

It is seen that all the numbers on right -side of the given equations consist of 3 digits. ∴ We can write

12 + 3 = abc

where a, b and c are in single digits.

Now we find that the digits 7, 8, 6 in the hundred place of the numbers 711, 820, 628 respectively are the numerical differences of the numbers on the left-hand-side of the equality; as,

7 = 9 - 2

8 = 14 – 6

6 = 17 - 11

Following this logic,

a = 12 - 3 = 9

To find bc, we observe that

11 = 2 + 9

20 = 14 + 6

28 = 17 + 11

∴ bc = 12 + 3 = 15

Hence 12 + 3 = 915 (Answer).

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