Question

9-22x+6x^3÷2x+4 divide explain it. ​

Answer 1

Answer:

I start with the long-division set-up:

long-division set-up

Looking only at the leading terms, I divide 3x3 by 3x to get x2. This is what I put on top:

x^2 up on top

I multiply this x2 by the 3x + 1 to get 3x3 + 1x2, which I put underneath:

3x^3 + 3x put down underneath the dividend

Then I change the signs, add down, and remember to carry down the "+10x – 3" from the original dividend, giving me a new bottom line of –6x2 + 10x – 3:

(3x^3 – 5x^2 + 10x – 3) – (3x^3 + 1x^2) = –6x^2 + 10x – 3