9(2a-b)^2-4(2a-b)-13
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Given : 9(2a−b)2−4(2a−b)−13
Let us consider 2a−b=c
So we get,
=9c2−4c−13
We can further write it as
=9c2−13c+9c−13
By taking out the common terms
=c(9c−13)+1(9c−13)
=(c+1)(9c−13)
Let us replace c by 2a−b
so we get
9(2a−b)2−4(2a−b)−13
Then,
=((2a−b)+1)(9(2a−b)−13)
∴9(2a−b)2−4(2a−b)−13=(2a−b+1)(18a−9b−13)
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