Math, asked by aayush3687, 1 year ago

9(2a-b)^2-4(2a-b)-13 factorise​

Answers

Answered by AccioNerd
14

Answer:

(2a - b + 1)(18a - 9b - 13)

Step-by-step explanation:

9(2a - b)² - 4(2a - b) - 13

= 9(2a - b)² + 9(2a - b) - 13(2a - b) - 13

= 9(2a - b)[(2a - b) + 1] - 13[(2a - b) + 1]

= 9(2a - b)(2a - b + 1) - 13(2a - b + 1)

= (2a - b + 1)[9(2a - b) - 13]

= (2a - b + 1)(18a - 9b - 13)

Hope this helps! :)


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Answered by Anonymous
7
HEYA MATE...••••✨✨

HERE'S YOUR ANSWER→♥❤

9 (2a-b)² - 4(2a-b)-13
write -4(2a-b) as a sum or difference.


→ 9(2a-b)² + 9(2a-b)-13(2a-b) -13
Factor out 9(2a-b) from the expression.


→ 9(2a-b)× (2a-b+1) -13 (2a-b) -13
Factor out -13 from the expression.


→ 9(2a-b)× (2a-b+1) -13 (2a-b+1)
Factor out 2a-b+1 from the expression.


→ (2a-b+1) × [9(2a-b)-13]


→ (2a-b+1) × (18a-9b-13)


Hope \: it \: helps...

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Anonymous: DO MARK IT AS THE BRAINLIEST IF YOU FIND IT HELPFUL...:-)...❤❤
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