Question

9.
2x2 + Kx + 3 = 0. If roots are equal then K is​

Answer 1

Answer :

k = ± $\sqrt{24}$

Explanation :

Given,

✶ 2x² + kx + 3 = 0

If roots are equal, it's determinant(∆) will be equal to zero.

→ ∆ = b² - 4ac

→ b² - 4ac = 0

→ (k)² - 4(2)(3) = 0

→ k² - 24 = 0

→ k = ± $\sqrt{24}$

Therefore,

$\boxed{k = ±\sqrt{24}}$

Answer 2

Step-by-step explanation:

2x^2+Kx+3=0 is quadratic equation.

roots are equal then discriminant is equal to zero.

b^2-4ac=0

K^2-4×2×3=0

K^2=24

$k = +- \sqrt{24}$