Question

9-3÷1\3+1=????
$9 - 3 \div \frac{1}{3} + 1 =$
whta is the answer​

Answer 1

Step-by-step explanation:

19 is the answer...

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Answer 2

➤ Answer :-

${\tt \longrightarrow 9 - 3 \div \dfrac{1}{3} + 1}$

Write all the numbers in fractional format..........

${\tt \longrightarrow \dfrac{9}{1} - \dfrac{3}{1} \div \dfrac{1}{3} + \dfrac{1}{1}}$

According to the BODMAS rule, first we should do division of fractions................

${\tt \longrightarrow \dfrac{3}{1} \div \dfrac{1}{3}}$

While dividing two fractions, first we should take the reciprocal of second fraction and multiply both the fractions...........

${\tt \longrightarrow \dfrac{3}{1} \times \dfrac{3}{1} = \dfrac{3 \times 3}{1}}$

${\tt \longrightarrow \dfrac{3}{1} = 3}$

Now, we should add the fractions............

${\tt \longrightarrow \dfrac{3}{1} + \dfrac{1}{1} = \dfrac{3 + 1}{1}}$

${\tt \longrightarrow \dfrac{4}{1} = 4}$

Now, we should subtract the fractions...........

${\tt \longrightarrow \dfrac{9}{1} + \dfrac{4}{1} = \dfrac{9 + 4}{1}}$

${\tt \longrightarrow \dfrac{13}{1} = \boxed{\tt 13}}$

$\Huge\therefore$ The answer is 13.

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More to know.................

• While adding or subtracting the fractions, if the given fractions are mixed fractions we should convert them into improper fractions by multiplying the denominator and whole number and then by adding the numerator.
• While adding or subtracting the fractions, if the given fractions are unlike fractions we should convert them into like fractions by taking the LCM of the denominators.
• While adding or subtracting the fractions, if the given fractions are like fractions we can solve them easily.