Question

9^-3*(16)^1/4/6^-2*(1/27)^-4/3

Answer 1

Answer:

I will thinking your question is wrong

Answer 2

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${9}^{ - 3} \times \frac{ {16}^{ \frac{1}{4} } }{ {6}^{ - 2} } \times ( \frac{1}{27} ) ^{ - \frac{4}{3} } \\ \\ = ( {3}^{2} ) ^{ - 3} \times \frac{ ({2}^{4}) ^{ \frac{1}{4} } }{(2 \times 3) ^{ - 2} } \times ( \frac{1}{ {3}^{3} } ) ^{ - \frac{4}{3} } \\ \\ = {3}^{2 \times ( - 3)} \times \frac{ {2}^{4 \times \frac{1}{4} } }{ {2}^{ - 2} \times {3}^{ - 2} } \times ( {3}^{ - 3} ) ^{ - \frac{4}{3} } \\ \\ {3}^{ - 6} \times \frac{ {2}^{1} }{ {2}^{ - 2} \times {3}^{ - 2} } \times {3}^{ - 3 \times (- \frac{4}{3} )} \\ \\ = {3 }^{ - 6} \times \frac{2}{ {2}^{ - 2} \times {3}^{ - 2} } \times {3}^{4} \\ \\ = {3}^{ - 6 + 2 + 4} \times {2}^{1 + 2} \\ \\ = {3}^{ - 6 + 6} \times {2}^{3} \\ \\ = {3}^{0} \times {2}^{3 } \\ \\ = 1 \times 8 \\ \\ = 8$

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