Question

(9+3/4) +(7+2/17) -(9+1/15) ​

Answer 1

Answer:

The value of $(9+\frac{3}{4} )+ (7+\frac{2}{17} )-(9+\frac{1}{15} )$ is $\frac{7957}{1020}$

Step-by-step explanation:

Given -

$(9+\frac{3}{4} )+ (7+\frac{2}{17} )-(9+\frac{1}{15} )$

To find -

The value of $(9+\frac{3}{4} )+ (7+\frac{2}{17} )-(9+\frac{1}{15} )$

Solution -

For addition or subtraction of fraction number both the denominator should be same.

First add

$(9+\frac{3}{4} )$

Multiply 9 by $\frac{4}{4}$ we get

= $\frac{36}{4}+\frac{3}{4}$

= $\frac{36+3}{4}$

= $\frac{39}{4}$

Second add

$(7+\frac{2}{17} )$

Multiply 7 by $\frac{17}{17}$ we get

= $\frac{119}{17}+\frac{2}{17}$

= $\frac{119+2}{17}$

= $\frac{121}{17}$

Lastly add

=$(9+\frac{1}{15} )$

Multiply 9 by $\frac{15}{15}$ we get

=  $\frac{135}{15} + \frac{1}{15}$

= $\frac{135+1}{15}$

= $\frac{136}{15}$

Now ,

= $\frac{39}{4}+\frac{121}{17}-\frac{136}{15}$

Add $\frac{39}{4}\:and\: \frac{121}{17}$

Multiply $\frac{39}{4}$ by $\frac{17}{17}$ and $\frac{121}{17}$ by $\frac{4}{4}$ we get

= $\frac{663}{68} + \frac{484}{68} -\frac{136}{15}$

= $\frac{663+484}{68} - \frac{136}{15}$

= $\frac{1147}{68} -\frac{136}{15}$

Multiply $\frac{1147}{68} \: by \: \frac{15}{15}\:and\: \frac{136}{15}\:by\:\frac{68}{68}$ we get

= $\frac{17205}{1020} -\frac{9248}{1020}$

= $\frac{17205-9248}{1020}$

= $\frac{7957}{1020}$

In Decimal 7.8

∴ The value of $(9+\frac{3}{4} )+ (7+\frac{2}{17} )-(9+\frac{1}{15} )$ is $\frac{7957}{1020}$ or 7.8