Question

(9)^3x-4 - (81)^4x-9 + (27)^x-27 = 168399

Answer 1

Answer:

${9}^{3x - 4} - 81 ^{4x - 9} + {27}^{x - 27} \\ = 168399$

This is a sum from exponents.

${9}^{3x - 4} - (9 ^{2} )^{4x - 9} + ( {3}^{3} )^{x - 27} \\ = 168399 \\ {9}^{3x - 4} - 9 ^{8x - 18} + 3 ^{3x - 81} \\ = 168399$

Now , do the prime factorisation of 168399.

Then, equate both the powers of LHS AND RHS.

now you will get the answer.

Thanking you