Question

((9/4)^(-3/2) (〖125/27)〗^(-2/3) (〖3/5)〗^(-2))/(√2)^4

Answer 1

Answer:

2/27

Step-by-step explanation:

hope it helps........

Answer 2

Answer:

The correct answer is $\frac{2}{27}$.

Step-by-step explanation:

Fraction rule: To add or subtract fractions they must contain the exact denominator (the bottom value). Addition and Subtraction with the exact denominators. If the denominators exist already the exact then it exists only as a matter of either adding or subtracting the numerators (the top value).

Given:

$\frac{\left(\frac{9}{4}\right)^{-\frac{3}{2}}\left(\frac{125}{27}\right)^{-\frac{2}{5}}\left(\frac{3}{5}\right)^{-2}}{(\sqrt{2})^{4}}$

To find:

the above equation.

Step 1

Let

$\frac{\left(\frac{9}{4}\right)^{-\frac{3}{2}}\left(\frac{125}{27}\right)^{-\frac{2}{5}}\left(\frac{3}{5}\right)^{-2}}{(\sqrt{2})^{4}}$

Simplifying the above equation, we get

$\left(\frac{9}{4}\right)^{-\frac{3}{2}}\left(\frac{125}{27}\right)^{-\frac{2}{3}}\left(\frac{3}{5}\right)^{-2}= \frac{8}{27}$

$=\frac{\frac{8}{27}}{(\sqrt{2})^{4}}$

Step 2

Apply the fraction rule, then we get

$\frac{\frac{a}{b}}{c}=\frac{a}{b \cdot c}$

$\frac{\frac{8}{27}}{(\sqrt{2})^{4}}$ $=\frac{8}{27(\sqrt{2})^{4}}$

$27(\sqrt{2})^{4}=108$

$=\frac{8}{108}$

Step 3

simplifying the fraction, then we get

$\frac{8}{108}= \frac{2}{27}$

$=\frac{2}{27}$

Therefore, the correct answer is $\frac{2}{27}$.

#SPJ2