9) агссотесі
4.
A block of mass 1 kg is placed on a rough wedge
which is fixed on an elevator moving upward with
constant velocity 2 m/s. The block m is at rest
W.r.t. wedge. Net reaction force on the block is
my
|| 2 m/s
L
30°
(1) 5N
(3) 7.5 N
(2) 10 N
(4) 12 N
Answers
Answer:
Force will be 10N.
Explanation:
As, from the question it is given that the block is kept perpendicular to the line of action of the force on the wedge hence there will be two component of forces out of which the force exerted will be on the horizontal direction.
So, the net fore will be F=mgsinθ where the value of the θ will be 90 degree and not 30 degree since the block is placed on wedge perpendicularly so the value of the net force F will be mgsin90 or mg = 1*10 = 10N.
Answer:
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11th
Physics
Laws of Motion
Motion Along a Rough Inclined Plane
A block of mass 1\ kg is ...
PHYSICS
A block of mass 1 kg is pushed against a rough vertical wall with a force of 20 N. coefficient of static friction being
4
1
. Another horizontal force of 10 N is applied on the block in a direction parallel to the wall. Will the block move? If yes, with what acceleration? If no, find the frictional force exerted by the wall on the block. (g=10 m/s
2
).
January 17, 2020
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Nishtha Gaurav
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ANSWER
Case I; F
2
in upward direction;
frictional force,
f
max
=μN=μF
1
=
4
1
×20=5N
Weight of mass =mg=1×10=10N
If F
2
in upward direction then
F
2
−mg=10−10=0
No frictional force acts and there is no acceleration.
Case II; F
2
in downward direction;
F
2
+mg−f
max
=ma
10+10−5=1.a
a=15m/s