Question

9. 40% of the passengers from a bus got off at station A, 75% of the remaining got off at station
remaining 12 passengers were taken to station C, find the original number of passengers

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Answer 1

Answer:

Let the total no. of passengers at the starting of the journey by \( x\).

Therefore,

of

Remaining no. of passengers

Now,

of

\( =9\times /20\)

So, remaining no. of passengers \( =\frac{3x}{5}-9\times /20=3x/20\)

\( A/Q\), \( 3x/20=12\)

\( \Rightarrow\;x=12\times\;20/3\)

\( \Rightarrow\;x=80\)

Therefore, original number of passengers is \( 80\)

Step-by-step explanation:

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Answer 2

Answer:

80

let total passegers be 10x

passengers at Station A = 10x × 40%= 4x

remaining passengers = 6x

75% of 6x = 3/4 × 6x = 9x/2

25% of 6x = 12 (given)

6x/4 = 12

x = 8

total passegers = 10×8=80