(9^-5)^2 divided by 27^6
Answers
Answer:
\Large{\bf{\green{\mathfrak{\dag{\underline{\underline{Given:-}}}}}}}†Given:−
Graph shows the positions of a body at different times.
\Large{\bf{\orange{\mathfrak{\dag{\underline{\underline{To \: Find:-}}}}}}}†ToFind:−
Speed of the body,
(i) A to B
(ii) B to C
(iii) C to D
\Large{\bf{\red{\mathfrak{\dag{\underline{\underline{Solution:-}}}}}}}†Solution:−
We know that,
\boxed{\pink{\sf Speed \: = \: \dfrac{Distance}{Time}}}Speed=TimeDistance
First let's take,
A to B
Distance covered from A to B =
Final distance covered - intial start =
3 - 0 = 3cm
Time taken =
Final time taken taken - starting time =
5 - 0 = 5s
Speed =
\sf Speed \: = \: \dfrac{3}{5}Speed=53
Therefore,
\boxed{\purple{\textsf{Speed from A to B = 0.6 cm/s.}}}Speed from A to B = 0.6 cm/s.
Second let's take,
B to C
Distance covered from B to C =
Final distance covered - initial start =
3 - 3 = 0cm
This implies that,
Body is at rest.
Time taken =
Final time taken - starting time =
7 - 5 = 2s
Speed =
Since, distance i.e numerator is 0.
Therefore,
\boxed{\purple{\textsf{Speed from B to C = 0 m/s i.e at rest.}}}Speed from B to C = 0 m/s i.e at rest.
Third let's take,
C to D
Distance covered from A to B =
Final distance covered - intial start =
7 - 3 = 4cm
Time taken =
Final time taken taken - starting time =
9 - 7 = 2s
Speed =
\sf Speed \: = \: \dfrac{4}{2}Speed=24
Therefore,
\boxed{\purple{\textsf{Speed from C to D = 2 cm/s.}}}Speed from C to D = 2 cm/s.
Finally,
Speed from A to B = 0.6 cm/s.
Speed from B to C = 0 cm/s.
Speed from C to D = 2 cm/s.
Step-by-step explanation:
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