Question

9.5 J of heat is required to increase of
the temperature of 3 moles of gase
from 40°C to 47°c at constant olome
The amount of heat required to raise
the same temperature at constant.
Preassure will be.​

Answer 1

Explanation:

Heat = moles(no.) ×C

P

×△T

⇒310=2×C

P

×10[35−25=10]

⇒C

P

=15.5J/molK

∴C

P

−C

V

=R

⇒C

V

=C

P

−R=15.5−8.314

⇒C

V

=7.186J/molK

Q=nC

V

△T

=2×7.186×10

=143.72J≈144J