Question

9.6×10²⁷/20

How to solve this? Explain in detail.​

Answer 1

Answer:

We know that charge must be integral multiples of 1⋅6×10

−19

C as charge of

one electron =1⋅6×10

−19

C

We cannot get any charge less than 1⋅6×10

−19

∴ we cannot get 9⋅6×10

−20

C

Answer 2

6×6=5/56544×34422553366543