Question

9^6-11 when divided by 8 would leave a remainder of

Answer 1

We know that 9/8 will leave a remainder '1'
Hence 9^6/8 will leave a remainder 1 [ or: x^n/x-1 will leave a remainder 1]
11/8 will leave a remainder 3
So 9^6 - 11 divided by 8=== rem(1) - Rem(3) divided by 8 = Rem(-2)/8
= 8 - 2 = 6 [ when the remainder is negative, subtract the remainder from divisor to get the actual remainder]
Hence, remainder = 6

Alternatively, you can calculate the value of 9^6 - 11 , then divide the result by 8 and find the remainder.
hope it helps.