Question

9
(6, 6)
Find a point on the X-axis which is equidistant from (2,-5) and (-2,9)​

Answer 1

Answer:

Step-by-step explanation:

let the given point be A(2,-5) and B(-2,9) and p point be p(x,0)

PA=PB=)PA^2=PB^2

=)(x-2)^2+(0+5)^2=(x+2)^2+(0-9)^2

=)x^2+4-4x+25=x^2+4x+4+81

=)-8x=56

x=-56/7

x=-8

point p will be (-7,0)

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