Question

9 , 65 , 26 , 126 odd term​

Answer 1

Answer:

9 and 65 are odd

Step-by-step explanation:

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Answer 2

Answer:

Required odd number is 26.

Step-by-step explanation:

Here given series is 9 , 65 , 26 , 126.

We want to find odd term of the series.

This is a problem of General inteligence part of Mathematics.

If we look it carefully then we can solve this problem easily.

Here all terms are maintaining a sequence.

Here,

9 = 3 x 3

28 = 7 x 4

65 = 13 x 5

126 = 21 x 6

It is clear that 26 is odd number here.

Therefore, required odd number is 26.

So important Mathematics formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

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