Math, asked by husna114ahmed, 5 months ago

9. 6a2 - 3ab-bc2c2factorise

Answers

Answered by johnjosephm54

0

Step-by-step explanation:

6a2 – 3a2b – bc2 + 2c2

= 6a2 – 3a2b + 2c2 – bc2 (By grouping)

= 3a2 (2 –b) + c2 (2 – b)

= (2 – b) (3a2 + c2)

Answered by hjfjb

0

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