Question

9+6d+d²=0
Solve it fast plz​

Answer 1

Answer:

1.1 Factoring d2+6d+9

The first term is, d2 its coefficient is 1 .

The middle term is, +6d its coefficient is 6 .

The last term, "the constant", is +9

Step-1 : Multiply the coefficient of the first term by the constant 1 • 9 = 9

Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is 6 .

-9 + -1 = -10

-3 + -3 = -6

-1 + -9 = -10

1 + 9 = 10

3 + 3 = 6 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 3

d2 + 3d + 3d + 9

Step-4 : Add up the first 2 terms, pulling out like factors :

d • (d+3)

Add up the last 2 terms, pulling out common factors :

3 • (d+3)

Step-5 : Add up the four terms of step 4 :

(d+3) • (d+3)

Which is the desired factorization