Question

(√9-√7),(√11-√5,)(√13-√3),(√10-√6) arrange in ascending order​

Answer 1

Step-by-step explanation:

Ascending order of √7- √5, √5 - √3, √9 - √7, √11 - √9: By rationalising √7- √5, we get 2/(√7 + √5) By rationalising √5 - √3, we get 2/(√5 + √3) By rationalising √9 - √7, we get 2/(√9 + √7) By rationalising √11 - √9, we get 2/(√11 + √9) On comparing 2/(√7 + √5), 2/(√5 + √3), 2/(√9 + √7), 2/(√11 + √9), Ascending order = [2/(√11 + √9)] < [2/(√9 + √7)] < [2/(√5 + √3)] < [2/(√7 + √5)] ⇒ (√11 - √9) < (√9 - √7) < (5 - √3) < (√7- √5)