Math, asked by shivamrajrajbhar974, 5 months ago

9
7
7. The area of a rectangle is 6a+b + 4b²a and its length is 2ab. The perimeter of the rectangle is
(a) 6a + 3b + 2ab
(b) 3a + 4b + 2ab
(c) Sa+60+qab
(d) 6a + 4b + 4

Answers

Answered by starboiiii

Answer:

2 and b 3, find the value,of a + b 2a -3b a. a2 +ab (v) 5a2 -2ab 3 . ... (d) 5a2 + 7b- 802, 4b + 3a2, 8a2-3b + 2c2 . ... 6 5. What should be added to 5a2+ 2ab to get 3a2-4ab?

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977. The area of a rectangle is 6a+b + 4b²a and its length is 2ab. The perimeter of the rectangle is(a) 6a + 3b + 2ab(b) 3a + 4b + 2ab(c) Sa+60+qab(d) 6a + 4b + 4​

Answers

9
7
7. The area of a rectangle is 6a+b + 4b²a and its length is 2ab. The perimeter of the rectangle is
(a) 6a + 3b + 2ab
(b) 3a + 4b + 2ab
(c) Sa+60+qab
(d) 6a + 4b + 4