Question

9.8×(2)²÷4×(3.14)² (explanation in words)​

Answer 1

Answer:

The length of a second's pendulum at a place where g = 9.8m/s 2 is 90.2 cm.

Step-by-step explanation:

What is the length of a seconds pendulum at a place where gravity equals the standard value of 9.80665 M s2?

It takes one second for it to go out (tick) and another second for it to come back (tock). What is the length of a seconds pendulum at a place where gravity equals the standard value of 9.80665 m/s2?

...

solution.

ℓ = (9.80665 m/s2)(2 s)2

4π2

(I'm in 8 grade pls make me Barinlist)

Answer 2

Answer:

length of second pendulum = 99.39cm

Step-by-step explanation:

$t \: = 2\pi \sqrt{ \frac{l}{g} } \\ t ^{2} = 4 {\pi}^{2} \times \frac{l}{g } \\ l = \frac{g \times ({t})^{2}}{4 {\pi}^{2} } = \frac{9.8 \times {2}^{2} }{4 \times ({3.14})^{2} } = 0.9939m = 99.39cm$