Question

9π/8-9/4sin^1/3=9/4sin^2√2/3,prove

Answer 1

Step-by-step explanation:

★ INVERSE TRIGONOMETRIC FUNCTIONS ★

Let π = @

9@/8 - 9/4sin^-1/3 =

Taking 9/4 common

9/4 [ @/2 - Sin^-1 1/3 ]

9/4 Cos^-1 1/3 = 9/4Sin^-1 √8/3

9/4 Sin^-1 2√2/3

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