Question

9.8 g of H2SO4 is dissolved in enough water to make 500 mL of solution. The molarity of H+ and So ion in the solution respectively are (Assume 100% ionisation of H2SO4, molar mass of H2SO4 = 98 g mol-1​

Answer 1

Answer:

0.05N

Explanation:

The molar mass of sulphuric acid is 98 g/mol.

Number of moles of sulphuric acid=

Molar mass of sulphuric acid

Mass of sulphuric acid

=

98g/mol

9.8g

=0.1mol

Molarity of the solution=

Volume of solution

Number of moles of sulphuric aicd

=

2L

0.1mol

=0.05M

I hope u will understand

Answer 2

Explanation:

Molarity is defined as the number of moles of an element or compound in 1L solution

As per given data, let us first calculate the number of moles of H2SO4.

Number of moles of 9.8g H2So4 = 9.8 /98 = 0.1 M H2So4

Now for 500ml, we have H2So4 is 0.1M

This means that for complete 1000mL solution, the molarity would come out as 0.2M

Then the molarity of H+ ions would be

= 2 × 0.2

= 0.4M