Question

9.8 g of sulphuric acid is dissolved in 18 g of water in a beaker. The numbers of oxygen atoms in the solution are: (Given: Sulphuric Acid = H2SO4)


8.432×1023


2.4 ×1023


6.023 ×1023


6.023 ×1021

Answer 1

Answer:

Option C is the Answer

hope this helps you

Answer 2

Answer:

8.432x1023

Explanation:

No. of moles of Sulphuric acid= Given mass/ molar mass = 9.8/98 = 0.1 mole

Moles of Oxygen atoms in given amount of sulphuric acid = 4x 0.1 =0.4 mole

Moles of water = 18/18 = 1

Moles of oxygen atoms in given amount of water= 1 mole

Total moles of oxygen = 0.4+1 = 1.4 moles

No. of atoms of oxygen = 1.4x6.023x1023 = 8.432 x1023