9×(81)^x=1/(27)^x-s
Find x
tejasri2:
give the value of s
Value of s is not given
Just need to find x
how to gind
find*
I dont know
I need the answer
Answers
Answered by
0
Hey dear!
Here is yr answer......
9 × 81^x = 1/(27)^x-3s
3^2 × 3^4x = 3^-3x -3s
3^2+4x = 3^-3x -3s
Here bases are equal... so the powers must be equal...
2+4x = -3x-3s
4x+3x = -3s-2
7x = -(3s+2)
x = -(3s+2)/7
Hope it hlpz...
Here is yr answer......
9 × 81^x = 1/(27)^x-3s
3^2 × 3^4x = 3^-3x -3s
3^2+4x = 3^-3x -3s
Here bases are equal... so the powers must be equal...
2+4x = -3x-3s
4x+3x = -3s-2
7x = -(3s+2)
x = -(3s+2)/7
Hope it hlpz...
is it right @ritu12579
Why you took 3s
Aravind
Answered by
0
Hi Friend !!!
Here is ur answer !!!
9×81^ x = 1/27^x-s
3²×3^ 4x = 3^-3(x-s)
3^(2+4x) = 3^-3x+3s
BASES ARE EQUAL EXPONENTS MUST BE EQUAL
2+4x = -3x+3s
4x+3x = 3s-2
7x = 3s-2
x = (3s-2)/7
Hope it helps u : )
Here is ur answer !!!
9×81^ x = 1/27^x-s
3²×3^ 4x = 3^-3(x-s)
3^(2+4x) = 3^-3x+3s
BASES ARE EQUAL EXPONENTS MUST BE EQUAL
2+4x = -3x+3s
4x+3x = 3s-2
7x = 3s-2
x = (3s-2)/7
Hope it helps u : )
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