Question

9.8gr of sulphuric acid is present in 500ml of solution calculate the molarity

plss answer me fast....​

Answer 1

Answer:

Molarity=no of moles /volume of solvent in (l)

Thus molarity=9.8/98×200×10^-3

=0.5

Thus molarity=0.5moles/L

Answer 2

Answer:

refer this..............