Question

9(a-2)^2-16(2a-3b)^2
factorize​

Answer 1

Required Answer:-

Given to factorise:

• 9(a - 2)² - 16(2a - 3b)²

Solution:

We know that,

➡ a² - b² = (a + b)(a - b)

Using this identity, we can factorise the given polynomial.

★ Here is the solution.

9(a - 2)² - 16(2a - 3b)²

Can be written as,

= 3²(a - 2)² - 4²(2a - 3b)²

= [3(a - 2)]² - [4(2a - 3b)]²

= (3a - 6)² - (8a - 12b)²

Now, using the identity, we get,

= [(3a - 6) + (8a - 12b)][(3a - 6) - (8a - 12b)]

= [3a - 6 + 8a - 12b][3a - 6 - 8a + 12b]

= (11a - 6 - 12b)(12b - 5a - 6)

Hence, the factorised form of the given polynomial is (11a - 6 - 12b)(12b - 5a - 6)

Answer:

• The factorised form of the given polynomial is (11a - 6 - 12b)(12b - 5a - 6)

Answer 2

Answer:

Heya mate here's the answer Mark as brainliest pleaseeeeee follow up