9(a-2)^2 - 16(a+2)^2
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Answered by
1
Hey mate!!!! Here the answer is :-
9(a-2)^2-16(a+2)^2
=Using identities:-(a-b)^2=a^2+b^2-2ab
(a+b)^2=a^2+b^2+2ab
=(a-2)^2=(a)^2+(2)^2-2(a)(2)=a^2+4-4a
=(a+2)^2=(a)^2+(2)^2+2(a)(2)=a^2+4+4a
Now, we get,
=9(a-2)^2-16(a+2)^2=9(a^2+4-4a)-16(a^2+4+4a)
=9a^2+36-36a-16a^2-64-64a
=9a^2-16a^2-36a-64a+36-64
=-7a^2-100a-28
Hope it will help you!!!!
alsaba58:
You were almost correct but your answere is wrong
Answered by
1
Hey mate see the right answer
9 (a-2)^2 - 16(a+2)^2
=9 ((a)^2+(2)^2-2×a×2)-16 (a)^2+(2)^2+2×a×2)
=9 (a^2+4-4a)-16 (a^2+4+4a)
=9a^2+36-36a-16a^2-64-64a
=9a^2-16a^2-36a-64a+36-64
=-7a^2-100a-28
Hope you are happy with answer
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