Question

9(a-2)^2-16(a+2)^2 factorise

Answer 1

Answer:

9(a-2)²-16(a+2)² =-(7a+2)(a+14)

Step-by-step explanation:

Given 9(a-2)²-16(a+2)²

= [3(a-2)]²-[4(a+2)]²

= (3a-6)²-(4a+8)²

= [(3a-6)+(4a+8)][(3a-6)-(4a+8)]

= (3a-6+4a+8)(3a-6-4a-8)

= (7a+2)(-a-14)

= -(7a+2)(a+14)

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