9. A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time
(i) the length of the shadow cast by another pole 10 m 50 cm high (ii) the height of a
pole which casts a shadow 5m long.
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9. A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time
(i) the length of the shadow cast by another pole 10 m 50 cm high (ii) the height of a
pole which casts a shadow 5m long.
Let x m be the length of the pole whose shadow is of length 10m50cm.
Let y m be the length of the pole whose shadow is 5m long.
Clearly, it is a case of direct variation.
i)
3.20
5.60
=
x
10.50
x=
5.60
10.50×3.20
=6
Hence, the length of the shadow is 6m.
ii)
3.20
5.60
=
5
y
x=
3.20
5.60×5
=8.75
Hence, the length of the pole is 8.75 meters.
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