Question

9. A 500 W electric iron is used every day for half an hour. Calculate the number of units
of electrical energy in kWh consumed by it in 30 days.
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Answer 1

Answer:

Power of electric iron = 500W

Time taken = 1/2 hr

energy consumed in one day = power × time

= 500 W × 1/2 hr

= 250 WHr

Energy consumed in 30 day = 30 × 250Whr

= 7500 Whr

energy consumed in KWhr = 7500Whr / 1000

= 7.5 KWhr

Answer 2

Answer:

Find the energy in kW h consumed in 10 hours by four devices of power 500 W each. Hence, the energy consumed by four equal rating devices in 10 h will be 4 — 5 kWh = 20 kWh = 20 Units.

Step-by-step explanation: