9.A 500W bulb emits monochromatic light of wavelength 400nm.Calculate the number of photons emitted per hour by the bulb.
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Answer:
Power of the bulb = 100 watt = 100Js
−1
Energy of one photon is E=hν=hc/λ
where, h=6.626×10
−34
Js,c=3×10
8
ms
−1
Given λ=400nm=400×10
−9
m
By putting the values, we get
E=6.626×10
−34
×3×10
8
/(400×10
−9
)
E=4.969×10
−19
J
Number of photons emitted in 1 sec × energy of one photon = power
n×4.969×10
−19
=100
n=
4.969×10
−19
100
n=2.012×10
20
photons per sec
Explanation:
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