Question

9. A 537 kg satellite orbits Earth with a speed of 4.3 km/s at a distance of 2.5 3 107 m from Earth’s centre.
(a) Calculate the acceleration of the satellite.
(b) Calculate the gravitational force on the satellite.

Answer 1

Explanation:

Iodine is a chemical element with the symbol I and atomic number 53. The heaviest of the stable halogens, it exists as a semi-lustrous, non-metallic solid at standard conditions that melts to form a deep violet liquid at 114 degrees Celsius, and boils to a violet gas at 184 degrees Celsius. Wikipedia

Symbol: I

Atomic mass: 126.90447 u

Atomic number: 53

Electron configuration: [Kr] 4d105s25p5

CAS ID: 7553-56-2

Discoverer: Bernard Courtois

Colors

Answer 2

ANS.

25 kilo-newtons

SOLUTION

Weight of satellite at earth surface       F=100 kN

Radius of earth      R=6400 km

Thus height above which the satellite is placed above the earth surface        h=12800−6400=6400  km

Weight of satellite at height h,         F′=FR2(R+h)2=F(1+hR)2

∴       F′=100(1+64006400)2=1004=25 kN